A 9.5-kg monkey is hanging by one arm from a branch and is swinging on a vertical circle. As an approximation, assume a radial distance of 80 cm between the branch and the point where the monkey's mass is located. As the monkey swings through the lowest point on the circle, it has a speed of 2.9 m/s.

(a) Find the magnitude of the centripetal force acting on the monkey.

centripetalforce= mass*v^2/r=9.5*2.9^2/.80

thanks you so much

To find the magnitude of the centripetal force acting on the monkey, we can use the formula:

F = m * v^2 / r

Where:
F is the centripetal force
m is the mass of the monkey
v is the velocity of the monkey
r is the radius of the circle

Plugging in the given values:
m = 9.5 kg
v = 2.9 m/s
r = 0.8 m (convert 80 cm to meters by dividing by 100)

F = 9.5 kg * (2.9 m/s)^2 / 0.8 m

Calculating:

F = 33.05 kg m^2/s^2 / 0.8 m

F = 41.31 N

Therefore, the magnitude of the centripetal force acting on the monkey is 41.31 Newtons.

To find the magnitude of the centripetal force acting on the monkey, we can use the centripetal force formula:

Fc = m * v^2 / r

Where:
Fc is the centripetal force
m is the mass of the monkey
v is the speed of the monkey
r is the radius of the circular path

In this case:
m = 9.5 kg (mass of the monkey)
v = 2.9 m/s (speed of the monkey)
r = 80 cm = 0.8 m (radius of the circular path)

Substituting these values into the formula, we have:

Fc = 9.5 kg * (2.9 m/s)^2 / 0.8 m

Calculating this expression:

Fc = 9.5 kg * 8.41 m^2/s^2 / 0.8 m
Fc = 100.295 N

So, the magnitude of the centripetal force acting on the monkey is approximately 100.295 N.