Please explain how you solve these problems.
It is greater than 43 and less than 52.If you add the digits,the sum is 8? This us confusing.
First list the numbers.
44, 45, 46, 47, 48, 49, 50, 51
Then add the digits:
44 = 4 + 4
45 = 4 + 5
and so on.
Which of the numbers has digits that add up to 8?
so it is 44, 45, 46, 47, 49, 49,50, 51
Now adding the digits, I see one where the sum is 8
So it must be 44.
thank u.
Got it! Thanks for making it simple.I think I was over analyzing it.
What is the pattern for these numbers 20, 24, 28, 32, 36?
To solve this problem, we need to find a number that is greater than 43 and less than 52, and whose digits add up to 8.
First, let's consider the possible two-digit numbers between 43 and 52: 44, 45, 46, 47, 48, 49, 50, 51.
We then need to determine if the sum of the digits of any of these numbers is 8.
For each number, we add the digits together:
44: 4 + 4 = 8 Yes, the sum is 8.
45: 4 + 5 = 9 No, the sum is not 8.
46: 4 + 6 = 10 No, the sum is not 8.
47: 4 + 7 = 11 No, the sum is not 8.
48: 4 + 8 = 12 No, the sum is not 8.
49: 4 + 9 = 13 No, the sum is not 8.
50: 5 + 0 = 5 No, the sum is not 8.
51: 5 + 1 = 6 No, the sum is not 8.
As we can see, the only number between 43 and 52 that fits the criteria is 44, where the sum of its digits is 8.
Therefore, the number that is greater than 43 and less than 52, and whose digits add up to 8, is 44.