2m+12=3m-31 3(5j+2) = 2(3j-6)

2m+12=3m-31

2m - 3m + 12 - 12 = 3m - 3m - 31 - 12
-1m = - 43

3(5j+2) = 2(3j-6)

15j + 6 = 6j - 12

Can you complete this problem? If you post your answer and work here, we'll be glad to check it for you.

Right! :-)

j = -2

5+3r=5r-19

To solve the equation 2m + 12 = 3m - 31, you will need to isolate the variable m on one side of the equation. Here are the steps to do that:

Step 1: Start by subtracting 2m from both sides of the equation:
2m - 2m + 12 = 3m - 2m - 31
12 = m - 31

Step 2: Next, add 31 to both sides of the equation:
12 + 31 = m - 31 + 31
43 = m

So the solution to the equation is m = 43.

Now let's solve the second equation, 3(5j + 2) = 2(3j - 6):

Step 1: Distribute the values outside the parentheses to the terms inside:
15j + 6 = 6j - 12

Step 2: Move all the terms involving j to one side of the equation by subtracting 6j from both sides:
15j - 6j + 6 = 6j - 6j - 12
9j + 6 = -12

Step 3: Subtract 6 from both sides:
9j + 6 - 6 = -12 - 6
9j = -18

Step 4: Divide both sides by 9:
(9j)/9 = (-18)/9
j = -2

Therefore, the solution to the second equation is j = -2.