I have tried virtually everything, i can't fogure out this problem. I have 2K^+ + SO4^2- + Ca^2+ + 2I^- --> CaSO4(s) + 2K^+ + 2I^-. but it is incorrect and i dnt see how, can u help me?
Write balanced complete ionic equation for K2SO4 (aq) + CaI2 (aq)CaSO4 (s) + KI(aq)?
To write a balanced complete ionic equation, you need to break down each compound into its individual ions and balance the charges on both sides of the equation.
Let's start by writing the reactants and products:
Reactants:
K2SO4(aq) + CaI2(aq)
Products:
CaSO4(s) + 2KI(aq)
Now, let's break down each compound into its ions:
Reactants:
K2SO4(aq) breaks down into 2K+ (cation) and SO4^2- (anion)
CaI2(aq) breaks down into Ca^2+ (cation) and 2I- (anion)
Products:
CaSO4(s) does not break down into ions since it is a solid.
2KI(aq) breaks down into 2K+ (cation) and 2I- (anion)
Now, let's write the balanced complete ionic equation:
2K+ (aq) + SO4^2- (aq) + Ca^2+ (aq) + 2I- (aq) -> CaSO4(s) + 2K+ (aq) + 2I- (aq)
As you can see, the balanced complete ionic equation is different from the equation you provided. Make sure you correctly break down each compound into its ions and balance the charges on both sides of the equation.
To write the balanced complete ionic equation for the reaction K2SO4 (aq) + CaI2 (aq) → CaSO4 (s) + 2KI (aq), you need to break down all the ionic compounds into their respective ions and write out the equation.
1. Start by writing the chemical equation:
K2SO4 (aq) + CaI2 (aq) → CaSO4 (s) + 2KI (aq)
2. Break down the ionic compounds into ions:
K2SO4 (aq) → 2K+ (aq) + SO4^2- (aq)
CaI2 (aq) → Ca^2+ (aq) + 2I^- (aq)
3. Write out the balanced complete ionic equation by combining the ions:
2K+ (aq) + SO4^2- (aq) + Ca^2+ (aq) + 2I^- (aq) → CaSO4 (s) + 2K+ (aq) + 2I^- (aq)
Now you have the balanced complete ionic equation for the reaction K2SO4 (aq) + CaI2 (aq) → CaSO4 (s) + 2KI (aq).
2K^+(aq) + SO4^-2(aq) + Ca^+2(aq) + 2I^-(aq) ==> CaSO4(s) + 2K^+(aq) + 2I^-(aq)
Are you omitting the (aq)? That could be the problem.