HBr is a molecular substance that is a strong acid in water. Write an equation for its ionization in water. Use minimal integer numbers to balance the reaction. Include physical states in your answer, e.g., start with HBr(l).
HBr(l) + H2O(l) ==> H3O^+(aq) + Br^-(aq)
Sure, here's an equation to showcase the ionization of HBr in water, with balanced coefficients and physical states:
HBr(l) + H₂O(l) → H₃O⁺(aq) + Br⁻(aq)
So, when HBr is dissolved in water, it undergoes ionization to produce positively charged hydronium ions (H₃O⁺) and negatively charged bromide ions (Br⁻). It's quite an electrifying process, don't you think?
The ionization of HBr in water can be represented by the following equation:
HBr(l) + H2O(l) → H3O+(aq) + Br-(aq)
In this equation, HBr acts as the acid and donates a proton (H+) to water (H2O) molecules. This proton combines with a water molecule to form the hydronium ion (H3O+), while the remaining part of the HBr molecule becomes the bromide ion (Br-).
To write the equation for the ionization of HBr in water, we should first write the molecular formula for HBr and then separate it into its constituent ions when dissolved in water.
The molecular formula for HBr is HBr(l), where (l) indicates that it is in the liquid state. When HBr is dissolved in water, it forms hydronium ions (H3O+) and bromide ions (Br-).
The balanced equation for the ionization of HBr in water can be written as follows:
HBr(l) + H2O(l) → H3O+(aq) + Br-(aq)
In this equation, (aq) indicates that the ions are in an aqueous (dissolved) state. The reaction can be represented further by using minimal integer numbers to balance the atoms on both sides of the equation.
1 HBr(l) + 1 H2O(l) → 1 H3O+(aq) + 1 Br-(aq)
Therefore, the ionization of HBr in water results in the formation of hydronium ions (H3O+) and bromide ions (Br-).