# science

Is 40ml of oil denser than 25ml of vinegar? and are most chemical changes easy or difficult to undo?

Density equals weight Divided by volume, so the amount of ml (volume) makes no difference. Vinegar is denser than oil. That's why when you put the 2 together, the oil floats on top.

density does NOT equal mass divided by volume. it is mass divided by volume. and there is a big difference between mass and weight. and mL is not the unit that goes with volume it is cc.

what are some things that use density to work????

Most hydrocarbons have a density around 0.7-0.8 g/mL. The motor oils I could find listed were shown (used motor oil, for example) at 0.89 g/mL. Vinegar is mostly water with a little acetic acid (about 4-5%). Since water is 1 g/mL, vinegar should be close to 1 g/mL. I found a typical 5% vinegar listed at 1.01 g/mL. Whether you use 40 mL or 25 mL makes no difference in this comparison.
As for chemical changes easy or difficult to undo, it all depends upon how you define easy and difficult. It also depends upon what chemical change we are trying to undo. For example, I have a chemical change if I strike a match and let it burn. But to change it back to a match would be MOST difficult. However, I can put hydrogen gas and oxygen gas in a container, add a spark or a match and it explodes. If I do this in a vessel and collect the product, which is water, then I can reverse this chemical change by electrolyzing the water back to hydrogen and oxygen gas (which is another chemical change). And I can switch back and forth between the two. I hope this helps.

1. 👍
2. 👎
3. 👁

## Similar Questions

1. ### science

A cylindrical bottle of oil-and-vinegar salad dressing whose volume is 1/3 vinegar (p=1.01 g/cm^3) and 2/3 oil (p=.910 g/cm^3) is at rest on a table. Initially the oil and the vinegar are separated, with the oil floating on top of

2. ### chem

vinegar is 5.0% acetic acid, CH3COOH, by mass. vinegar has a density of 1.02 g/ml what is the madd of acetic acid in 50.0 ml of vinegar?

3. ### Math

The ratio of oil to vinegar in a certain salad dressing is 8:5. How much oil must be blended with 7 liters of vinegar for that recipe?

4. ### Chem Lab

Am I right? Classify the following properties of sodium metal as physical or chemical: •Silver metallic color—physical property •Turns gray in air—physical property •Melts at 98º C-melting point is physical property

1. ### Chemistry

If acetic acid is the only acid that vinegar contains [Ka = 1.8*10-5] , calculate the concentration of acetic acid in the vinegar. pH of vinegar is 3.20 _______________ First I got the antilog of the pH given, which turned out to

2. ### Chemistry

Vinegar is a solution of acetic acid, CH3COOH, dissolved in water. A 4.69 g sample of vinegar was neutralized by 32.97 mL of 0.100 M NaOH. What is the percent by weight of acetic acid in the vinegar?

3. ### Chemistry

A particular vinegar contains 4.0% CH3COOH by mass. It reacts with sodium carbonate to produce sodium acetate, carbon dioxide, and water. How many grams of carbon dioxide are produced by the reaction of 5.00 mL of this vinegar

4. ### 11th grade CHEMISTRY TITRATION LAB!

i have a tritation lab due tomorrow and i am stumped on a couple things. its a titration lab using sodium hydroxide (NaOH)- 250 mL 0.300 M concentration, 10 mL of an unknown substance of vinegar, the avg. of titrated NaOH in the

1. ### chemistry

is motor oil a homogeneous mixture or a compound? why? is iron smelting a chemical or physical process? I call oil a homogeneous mixture. Look up the definition of a mixture and the definition of a compound. Motor oil contains a

2. ### Chemistry

Assuming the density of vinegar is 1.0 g/mL ' what is the molarity of vinegar? (use the percent by mass of acetic acid to vinegar which is 5%.) The molar mass of acetic acid is 60.05 g/mol?

3. ### chemistry

10 ml sample of vinegar an aqueous solution 0f acetic acid( HC2H3O2) is titrated with 0.5062 M and 16.58 ml is required to reach equivalence point what is the molarity of the acetic acid b. if the density of vinegar is 1.006 g/cm3

4. ### chemistry step by step for me Bob

A sample of peanut oil weighing 2g is added to 25ml of 0.4M koh. After saponification is complete, 8.5ml of 0.28M hes04 is needed to neutralize excess of koh. The saponification number of peanut oil. The right answer 146.75 Bob