An object is thrown vertically upward with a speed of 31.8 m/s. How high does it rise?

at the top v=0

vf^2=Vi^2+2gh

g=-9.8m/s^2 solve for h.

To find the height the object reaches, we can use the equations of motion. When an object is thrown vertically upward, we can use the following equation:

v^2 = u^2 + 2as

Where:
v = final velocity (which is zero when the object reaches its highest point)
u = initial velocity
a = acceleration (in this case, due to gravity, a is -9.8 m/s^2)
s = displacement or height

Let's calculate the height:

Given:
u = 31.8 m/s
v = 0 m/s
a = -9.8 m/s^2

Using the equation:
0^2 = 31.8^2 + 2(-9.8)s

Rearranging the equation:
0 = 1011.24 - 19.6s

19.6s = 1011.24

s = 1011.24 / 19.6

s ≈ 51.6 meters

Therefore, the object rises to a height of approximately 51.6 meters.