A car is moving down a street at 51 km/h. A child suddenly runs into the street. If it takes the driver 0.97 s to react and apply the brakes, how many meters will the car have moved before it begins to slow down?

51 km/h * 1000 m/km * 1/3600 h/s =

14.17 m/s.

d = v * t = 14.17 m/s * 0.97 s = 13.74 m.

To find out how many meters the car will have moved before it begins to slow down, we can use the concept of average velocity.

Average velocity is defined as the total distance traveled divided by the total time taken. Therefore, we need to calculate the distance traveled by the car during the reaction time.

Given:
- Initial velocity of the car (v₀) = 51 km/h
- Reaction time (t) = 0.97 s

First, we need to convert the initial velocity from km/h to m/s, as the reaction time is given in seconds.

Conversion:
1 km/h = 1000 m / (60 × 60) s [1 hour = 60 minutes = 60 seconds]

v₀ = 51 km/h × (1000 m / (60 × 60) s) = 14.17 m/s

The distance traveled during the reaction time can be calculated using the equation:
Distance = Initial velocity × Time

Distance = v₀ × t
= 14.17 m/s × 0.97 s
≈ 13.73 m

Therefore, the car will have moved approximately 13.73 meters before it begins to slow down.