Chemistry

A volume of 50.0 mL of aqueous potassium hydroxide was titrated against a standard solution of sulfuric acid. What was the molarity of the KOH solution if 19.2 mL of 1.50 M H2SO4 was needed? The equation is

2KOH(aq) +H2SO4(aq)-ยป K2SO4(aq)+2H2O(l)

asked by Ellen
  1. moles H2SO4 = M x L.
    From the equation, moles KOH must be twice moles H2SO4.
    M KOH = moles/L.

    posted by DrBob222

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