If I take a glob of mud and throw it against a wall with the speed of V and stops in time T and than I take a ball and throw it and it hits the wall with speed V and leaves the wall a time T later at a speed of 0.5V and they both have same value and mass, which one involves a greater total force on the object.
I think it is the ball but I don't why
Can you tell me I should start on this
To determine which object experiences a greater total force, we need to analyze the forces acting on both the mud ball and the ball.
First, let's consider the mud ball. When you throw the mud ball against the wall, it decelerates and ultimately stops upon impact. The stopping of the mud ball is due to the force exerted by the wall, which is known as the normal force. In this case, the normal force acts in the opposite direction of the mud ball's motion, causing it to slow down and eventually come to a stop. The force required to bring the mud ball to rest in time T is greater than the force required to maintain its steady speed of V. This is because the mud ball is decelerating, and a greater force is needed to slow it down and counteract its initial momentum.
On the other hand, let's consider the ball. When the ball hits the wall with a velocity of V, it rebounds with a velocity of 0.5V. During collision with the wall, the ball experiences a force due to the change in momentum. This force is larger compared to the force experienced by the mud ball because the ball experiences a more significant change in velocity. The greater change in velocity results in a larger change in momentum, and thus a larger force is exerted on the ball.
Therefore, in this scenario, the ball involves a greater total force on the object compared to the mud ball.