if the mean bp is 110 and the standard deviation is 15 where would 95% of population be

http://davidmlane.com/hyperstat/z_table.html

Try in the region of 135

Also you can find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion indicated. Insert Z score value in the formula below and solve for the score.

Z = (score-mean)/SD = (score-110)/15

This method does not require a computer or electricity.

To find where 95% of the population would be, we need to use the concept of the standard normal distribution and the z-score.

1. Start by finding the z-score associated with the desired percentage. In this case, we want to find the z-score that corresponds to an area of 95% in the standard normal distribution.

2. Look up the z-score in a standard normal distribution table or use a calculator. For 95%, the z-score is approximately 1.96.

3. Use the z-score formula to calculate the desired value. The z-score formula is: Z = (X - μ) / σ, where Z is the z-score, X is the observed value, μ is the mean, and σ is the standard deviation.

4. Rearrange the formula to solve for the observed value, X. In this case, we have: X = Z * σ + μ.

Now let's plug in the values:

X = 1.96 * 15 + 110

Calculating this, we get:

X ≈ 143.4

Thus, approximately 95% of the population would have a blood pressure within 143.4 units.