How many ions are produced when a formula unit of Li2CO3 is dissolved in water?
Two lithium ions, one carbonate ion: 3 ions
When a formula unit of Li2CO3 is dissolved in water, it dissociates into its constituent ions. Each Li2CO3 formula unit contains one lithium ion (Li+) and one carbonate ion (CO32-).
Since there are two lithium ions (Li+) per formula unit, the total number of ions produced when a formula unit of Li2CO3 is dissolved in water is 2 + 1 = 3 ions.
To determine how many ions are produced when a formula unit of Li2CO3 (lithium carbonate) is dissolved in water, we need to break down the compound into its respective ions.
The formula unit of Li2CO3 tells us that there are two lithium (Li) ions, one carbonate (CO3) ion, and three oxygen atoms. However, only the lithium and carbonate ions will dissociate in water.
Given that lithium (Li) is an alkali metal and typically forms a +1 charge, each Li2CO3 formula unit will release two Li+ ions when dissolved in water.
Similarly, the carbonate (CO3) ion, which is a polyatomic ion with a -2 charge, will release one CO3^2- ion in water.
So, when a formula unit of Li2CO3 is dissolved in water, it will produce two Li+ ions and one CO3^2- ion.
Therefore, the total number of ions produced is 2 + 1 = 3.