calculus

1) Solve for x in terms of k:

log3(x) + log3(x+7) = k; 3 is the base

2) e^(x+5) = e^(x) + 6, solve for x.

Please help, I have no idea how to do these and I've tried several times!

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  1. log3x +log3(x+7)=log3(x)(x+7)
    then take the antilog of each side.

    x(x+7)=3^k then, this will be a quadratic equation.

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    bobpursley

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