if the circumference of a circle is 16 meters,what is the approximate area of the circle

Hi. I hope I can help you with this question.

The formula for circumference is pi times the diameter :
C = pi * d
Since pi is already known, as well as the circumference. You can solve for d.
Now you have the circle's diameter. Half of that is its radius.
The area of a circle is as followed:
A = pi * (radius)^2
since you know pi, and you now know the radius, i'm pretty sure you can finish it out. Hope this helped. Peace.

To find the approximate area of a circle, we can use the formula:

A = πr^2

where A is the area and r is the radius of the circle.

Given that the circumference of the circle is 16 meters, we can calculate the radius (r) by using the formula for circumference:

C = 2πr

Plugging in the given value of the circumference, we have:

16 = 2πr

To isolate r, we divide both sides of the equation by 2π:

16 / (2π) = r

Now, we can substitute the value of r into the area formula to find the approximate area:

A = π(16 / (2π))^2

Simplifying:

A = π(8 / π)^2
= 64π / π^2
≈ 64 / π

So, the approximate area of the circle is 64 / π square meters.

To find the approximate area of a circle, we need to know either the radius or the diameter. In this case, we only have the circumference, which is the distance around the circle.

The formula for the circumference of a circle is C = 2πr, where C is the circumference and r is the radius. Rearranging this equation to solve for the radius, we have r = C / (2π).

Given the circumference of 16 meters, we can substitute this value into the equation to find the radius: r = 16 / (2π) ≈ 2.546 meters.

To find the area of the circle, we can use the formula A = πr^2, where A is the area and r is the radius. Plugging in the approximate value of the radius we found earlier, we have A ≈ π(2.546)^2.

Evaluating this expression, we find that the approximate area of the circle is A ≈ 20.285 square meters.

C = pi * d

16 = 3.14 * d
16/3.14 = 5.0955

5.0955 / 2 = 2.5478

Use 2.5478 for the radius and the formula I posted to your last question to find the area.