Calcu-
late the mass of pure acetic acid in 440 mL of
this solution at 20 C.
Answer in units of g.
You must finish the problem.
i came up with the answer of 419 g
Th solution has a density of 1.049g/mL and only 40% of the solution is acetic acid
At normal temperature and pressure, air has
a density of 0.001184 g/mL. What is the mass
of air in a room that is 3.74 m by 3.45 m by
3.93 m?
Answer in units of kg.
For the acetic acid problem I don't think the answer is 419 g. You can check it if you wish.
419 g/440 mL
440 mL with a density of 1.049 g/mL = mass of 440 x 1.049 = 461.6 grams and
(419/461.6)*100 = 90.7%; that isn't 40% so it must not be right.
For the air problem, I would convert each of the length, width, height in meters to cm, multiply to obtain volume in cc, then multiply by density to obtain grams air. Convert to kg.
To calculate the mass of pure acetic acid in a solution, you need to know the concentration of acetic acid in the solution. Since the concentration is not provided in your question, it is not possible to accurately calculate the mass of pure acetic acid.
If you have the concentration of acetic acid in the solution, you can use the formula:
Mass of acetic acid = Volume of solution (in liters) × Concentration of acetic acid × Density of acetic acid
Here's the step-by-step process to find the mass of pure acetic acid when the concentration is given:
1. Convert the volume of the solution to liters:
- 440 mL ÷ 1000 = 0.440 L
2. Multiply the volume of the solution by the concentration of acetic acid. Make sure the units are consistent:
- Mass of acetic acid = 0.440 L × Concentration of acetic acid (in units of mol/L)
3. Convert the concentration of acetic acid to moles if it's not already in moles per liter (mol/L).
4. Finally, multiply the number of moles by the molar mass of acetic acid to get the mass of pure acetic acid in grams.
Please provide the concentration of acetic acid so that I can guide you further in calculating the mass.