How many grams of NaCl are dissolved in 250 grams of normal saline solution
Since, Normal Saline Solution is 0.91% w.v solution of NaCl which means the solution should contain 0.91% of NaCl by weight, for which take the 0.91% of total volume (250ml)-(I think you have mistaken, it must be 250ml not gms, since solution is measured in ml, litre etc.
Solution:
Amount of NaCl required in gms = 0.91% of Volume of solution,
Amount of NaCl required in gms = 0.91% of 250
Amount of NaCl required in gms = 2.27grams.
Hope it helps.
Normal saline contains 0.91% w/v of NaCl, meaning mass/volume, or 0.91grams of NaCl per 100 ml of solution. The sterile form of this saline is used for IV drips.
Other concentrations are also available.
This w/v unit is convenient to obtain mass by measuring volume, especially useful in medical situations where measuring volume is much faster than measuring mass.
To determine the number of grams of NaCl dissolved in 250 grams of normal saline solution, we need to know the concentration of the solution.
Normal saline solution typically refers to a solution containing 0.9% (w/v) NaCl, which means there is 0.9 grams of NaCl per 100 mL of solution.
First, let's convert the 250 grams of normal saline solution to milliliters:
250 grams * (1 mL / 1 gram) = 250 mL
Next, we can calculate the amount of NaCl in the 250 mL of solution:
0.9 grams NaCl / 100 mL * 250 mL = 2.25 grams NaCl
Therefore, there are 2.25 grams of NaCl dissolved in 250 grams of normal saline solution.
To determine the number of grams of NaCl dissolved in 250 grams of normal saline solution, we need to know the concentration of NaCl in the solution. Normal saline solution, also known as 0.9% saline solution, typically contains 0.9 grams of NaCl per 100 milliliters (ml) of solution.
First, let's convert 250 grams of normal saline solution to milliliters. Since the density of saline solution is approximately 1 gram/ml, 250 grams is equal to 250 ml.
Next, we calculate the amount of NaCl in 250 ml of saline solution. Since there are 0.9 grams of NaCl in 100 ml of solution, we can set up a proportion:
0.9 grams NaCl / 100 ml = x grams NaCl / 250 ml
Cross-multiplying, we get:
0.9 * 250 = 100 * x
225 = 100x
Dividing both sides by 100, we find:
x = 2.25 grams
Therefore, there are approximately 2.25 grams of NaCl dissolved in 250 grams of normal saline solution.