A football punter accelerates a 0.58 kg foot-
ball from rest to a speed of 7.0 m/s in 0.25
s.What constant force does the punter exert
on the ball?
Answer in units of
To find the constant force exerted by the punter on the ball, we can use Newton's second law of motion:
F = ma
Where:
F is the force (in newtons),
m is the mass of the ball (in kilograms), and
a is the acceleration of the ball (in meters per second squared).
In the given scenario, the ball starts from rest and achieves a final speed of 7.0 m/s in a time of 0.25 seconds.
To find the acceleration, we can use the formula for acceleration:
a = Δv / Δt
Where:
Δv is the change in velocity (final velocity - initial velocity),
Δt is the change in time (final time - initial time).
Given that the initial velocity is 0 m/s and the final velocity is 7.0 m/s, and the change in time is 0.25 seconds, we can calculate the acceleration:
a = (7.0 m/s - 0 m/s) / 0.25 s
a = 28 m/s^2
Now, we can calculate the force applied by the punter using Newton's second law of motion:
F = (0.58 kg) * (28 m/s^2)
F = 16.24 N
Therefore, the constant force exerted by the punter on the ball is 16.24 newtons.