If a 6.00M solution of sodium hydroxide occupies 520 mL of space how many grams of NaOH is dissolved in the solution? (Remember M = moles/L). And the work.
M = moles/L
You have M and L, solve for mols.
Then moles = grams/molar mass
You have moles and molar mass, solve for grams.
6.00M*.520L= 3.12Moles of NaOH
3.12 mols*40= 124.8 grams of NaOH
To find the number of grams of sodium hydroxide (NaOH) dissolved in the solution, we need to use the given molarity (M) and volume (L) of the solution.
First, convert the volume from milliliters (mL) to liters (L):
520 mL = 520 / 1000 L = 0.520 L
Now, we can use the formula M = moles/L to find the number of moles of NaOH in the solution.
Rearranging the formula, we have moles = M × L.
Given that the molarity of the solution is 6.00 M and the volume is 0.520 L, we can substitute these values into the equation:
moles = 6.00 M × 0.520 L = 3.12 moles.
Finally, to calculate the mass of NaOH, we need to use the molar mass of NaOH, which is 22.99 g/mol (for Na) + 16.00 g/mol (for O) + 1.01 g/mol (for H) = 39.00 g/mol.
The mass of NaOH is given by the equation mass = moles × molar mass:
mass = 3.12 moles × 39.00 g/mol = 121.68 grams.
Therefore, there are 121.68 grams of NaOH dissolved in the solution.
To summarize the steps:
1. Convert the volume from mL to L: 520 mL = 0.520 L.
2. Use the formula moles = M × L, substituting the given values: moles = 6.00 M × 0.520 L = 3.12 moles.
3. Calculate the molar mass of NaOH: 22.99 g/mol (Na) + 16.00 g/mol (O) + 1.01 g/mol (H) = 39.00 g/mol.
4. Use the equation mass = moles × molar mass, substituting the values: mass = 3.12 moles × 39.00 g/mol = 121.68 grams.