which of the followign reactions is the complete ion equation for the reaction between sodium sulfide and mercury(II) chloride?
a. s2-+Hg2+=hgs
b. na2s+hgcl2= 2nacl+hgs
c. nas+hgcl2=nacl+hgs
d. 2na+ +s2- +2cl- +hg2+= 2na+ +2cl-+hgs
None of the answers are correct because you didn't write the formulas correctly.
hgs means nothing to anyone.
To determine the complete ionic equation for the reaction between sodium sulfide (Na2S) and mercury(II) chloride (HgCl2), we need to know the formulas and charges of the individual ions involved.
The formula for sodium sulfide is Na2S. When it dissolves in water, it dissociates into two sodium ions (Na+) and one sulfide ion (S2-).
The formula for mercury(II) chloride is HgCl2. When it dissolves in water, it dissociates into one mercury(II) ion (Hg2+) and two chloride ions (2Cl-).
Now let's analyze the given options:
a. s2- + Hg2+ = HgS
This option is not balanced and does not represent the individual ions correctly.
b. Na2S + HgCl2 = 2NaCl + HgS
This option correctly represents the reaction and the balanced equation. It shows that sodium sulfide reacts with mercury(II) chloride to form two molecules of sodium chloride (2NaCl) and one molecule of mercury(II) sulfide (HgS).
c. NaS + HgCl2 = NaCl + HgS
This option does not represent the balanced equation because it only includes one sodium ion (Na+) instead of two.
d. 2Na+ + S2- + 2Cl- + Hg2+ = 2Na+ + 2Cl- + HgS
This option is not balanced because it includes two sodium ions (2Na+) on the reactant side but only one on the product side.
Based on the analysis, the correct answer is option b. Therefore, the complete ionic equation for the reaction between sodium sulfide and mercury(II) chloride is:
Na2S(aq) + HgCl2(aq) = 2NaCl(aq) + HgS(s)