a ball rolling down a hill uniformly accelerated at 4 m/s2. assumong that it start from rest, what is its speed at the end of each of the first 3 s?
vf=a*t
To find the speed of a ball rolling down a hill uniformly accelerated at 4 m/s² at different time intervals, we can use the following equation:
v = u + at
Where:
v is the final velocity (speed) of the ball,
u is the initial velocity of the ball,
a is the acceleration,
t is the time.
Given that the ball starts from rest (u = 0 m/s) and the acceleration is 4 m/s², we can calculate the speed of the ball at different time intervals.
At time t = 1 second:
v₁ = u + at
v₁ = 0 + (4 m/s²)(1 s)
v₁ = 4 m/s
At time t = 2 seconds:
v₂ = u + at
v₂ = 0 + (4 m/s²)(2 s)
v₂ = 8 m/s
At time t = 3 seconds:
v₃ = u + at
v₃ = 0 + (4 m/s²)(3 s)
v₃ = 12 m/s
Therefore, the speed of the ball at the end of the first, second, and third second is 4 m/s, 8 m/s, and 12 m/s respectively.