Find n so that the square and triangle have the same perimeter. The square is 8n+6, the triangle is 13n+2 on two of the sides and 30n-28 on the other side. This is the question that I have for homework,I don't understand it. Thanks
Check your other post, already answered. Please don't repost.
To find the value of n where the square and triangle have the same perimeter, we need to set up an equation using the given information.
Let's start by finding the perimeter of the square. The perimeter of a square is calculated by multiplying the length of one side by 4. In this case, the length of one side of the square is given as "8n+6". So the perimeter of the square is equal to 4 * (8n+6).
Similarly, let's find the perimeter of the triangle. The perimeter of a triangle is calculated by adding the lengths of all its sides. In this case, the triangle has two sides with lengths "13n+2" and one side with length "30n-28". So the perimeter of the triangle is equal to (13n+2) + (13n+2) + (30n-28).
According to the given information, the perimeter of the square is equal to the perimeter of the triangle. Therefore, we can set up the equation:
4(8n+6) = (13n+2) + (13n+2) + (30n-28)
Simplifying this equation will give us the value of n.
16n + 24 = 26n - 24
Rearranging the equation:
16n - 26n = -24 - 24
-10n = -48
Dividing both sides of the equation by -10:
n = (-48) / (-10)
n = 4.8
So, the value of n where the square and triangle have the same perimeter is 4.8.