find n so that squares and triangle has the same perimeter square is 8n+6 triangle is 13n+2 on two sides and 30n-28 on the other
Without appropriate punctuation and capitalization, I don't understand what you're asking.
Find n so that the square and triangle have the same perimeter. The square is 8n+6, the triangle is 13n+2 on two of the sides and 30n-28 on the other side. This is the question that I have for homework,I don't understand it. Thanks
I think you set it up like this..not positive though:
4(8n+6)=2(13n+2)+30n-28
Jen is correct
just solve her equation, it's easy
To find the value of n for which the square and triangle have the same perimeter, we need to equate their perimeters and solve for n.
Let's start by finding the perimeter of the square. The formula for the perimeter of a square is P = 4s, where P is the perimeter and s is the length of a side.
The square has a perimeter of 8n + 6, so we can set up the equation:
8n + 6 = 4s
Next, let's find the perimeter of the triangle. The formula for the perimeter of a triangle is P = a + b + c, where P is the perimeter and a, b, c are the lengths of the sides.
The triangle has sides of length 13n + 2, 13n + 2, and 30n - 28, so the equation becomes:
P = (13n + 2) + (13n + 2) + (30n - 28)
Now, equating the perimeters of the square and triangle, we have:
8n + 6 = (13n + 2) + (13n + 2) + (30n - 28)
Simplifying the equation:
8n + 6 = 26n - 24
Combine like terms:
8n - 26n = -24 - 6
-18n = -30
Divide both sides by -18 to solve for n:
n = (-30) / (-18)
n = 5/3
Therefore, the value of n for which the square and triangle have the same perimeter is n = 5/3.