solve the inequality
8/x-3 > 6/x-1
Unless you show parentheses, I have no idea if you mean 8/(x-3) or (8/x) -3. The same goes for 6/(x-1) vs (6/x) -1. Please restate your question.
8 6
----- > ----- = ?
x - 3 x - 1
8 / (over) x-3 > 6 / (over) x-1 =
like a fraction bar
To solve the inequality 8/(x-3) > 6/(x-1), we can start by multiplying both sides of the inequality by (x-3)(x-1) to eliminate the denominators.
This gives us:
8(x-1) > 6(x-3)
Now, let's distribute the terms on both sides of the inequality:
8x - 8 > 6x - 18
Next, we can isolate the variable term by subtracting 6x from both sides:
8x - 6x - 8 > -18
Simplifying further, we have:
2x - 8 > -18
To isolate the variable term, we can add 8 to both sides of the inequality:
2x - 8 + 8 > -18 + 8
Simplifying, we get:
2x > -10
Finally, we divide both sides of the inequality by 2 to solve for x:
(2x)/2 > (-10)/2
This simplifies to:
x > -5
So, the solution to the inequality 8/(x-3) > 6/(x-1) is x > -5.