solve the inequality

8/x-3 > 6/x-1

Unless you show parentheses, I have no idea if you mean 8/(x-3) or (8/x) -3. The same goes for 6/(x-1) vs (6/x) -1. Please restate your question.

8 6

----- > ----- = ?
x - 3 x - 1

8 / (over) x-3 > 6 / (over) x-1 =

like a fraction bar

To solve the inequality 8/(x-3) > 6/(x-1), we can start by multiplying both sides of the inequality by (x-3)(x-1) to eliminate the denominators.

This gives us:

8(x-1) > 6(x-3)

Now, let's distribute the terms on both sides of the inequality:

8x - 8 > 6x - 18

Next, we can isolate the variable term by subtracting 6x from both sides:

8x - 6x - 8 > -18

Simplifying further, we have:

2x - 8 > -18

To isolate the variable term, we can add 8 to both sides of the inequality:

2x - 8 + 8 > -18 + 8

Simplifying, we get:

2x > -10

Finally, we divide both sides of the inequality by 2 to solve for x:

(2x)/2 > (-10)/2

This simplifies to:

x > -5

So, the solution to the inequality 8/(x-3) > 6/(x-1) is x > -5.