How do you solve this?
(3x+2)(3x^2+5x-4)
(3x + 2)(3x^2 + 5x - 4)
multiply:
9x^3 + 15x^2 - 12x + 6x^2 + 10x - 8,
Combine like-terms:
9x^3 + 21x^2 - 2x - 8,
Group the 4 terms into factorable pairs:
(9x^3 + 21x^2) + (-2x - 8),
3x^2(3x + 7) -2(x + 4),
This cannot be completely factored.
NOPE!!!!!!!!!!!!!!!!!!!! I can't solve it. Sorry. :-(
To solve the expression (3x+2)(3x^2+5x-4), we can use the distributive property and the rules of multiplying binomials.
Step 1: Distribute the first term of the first binomial (3x) to every term inside the second binomial:
(3x) * (3x^2 + 5x - 4)
This becomes:
(9x^3 + 15x^2 - 12x)
Step 2: Distribute the second term of the first binomial (2) to every term inside the second binomial:
(2) * (3x^2 + 5x - 4)
This becomes:
(6x^2 + 10x - 8)
Step 3: Add the products obtained from Step 1 and Step 2 together:
(9x^3 + 15x^2 - 12x) + (6x^2 + 10x - 8)
Combine like terms:
9x^3 + 15x^2 - 12x + 6x^2 + 10x - 8
Now, let's simplify further:
Combine the x^2 terms:
9x^3 + (15x^2 + 6x^2) - 12x + 10x - 8
9x^3 + 21x^2 - 12x + 10x - 8
Combine the x terms:
9x^3 + 21x^2 + (10x - 12x) - 8
9x^3 + 21x^2 - 2x - 8
The solution to the expression (3x+2)(3x^2+5x-4) is 9x^3 + 21x^2 - 2x - 8.