A student placed 12.0g of glucose (C6H1206) in a volumetric flask, added enough water to dissolve the glucose by swirling, then carefully added additional water until the 100.-ml mark on the neck of the flask was reached. The flask was then shaken until the solution was uniform. A 50.0-ml sample of this glucose solution was diluted to 0.500 L. How many grams of glucose are in 100 ml of the final solution?
m=12grams
Molar Mass= 180.18
V=.1L
n= m/MM= 0.067 moles.
Molarity= n/V= .067/.1= .67
M1V1=M2V2 => 0.67(.05)=M2(.5)
Solve for M2 and you get .067
M= m/VMM : Molarty= mass/ Volume x Molar Mass
so m= MVMM : mass= Molarity x Volume x Molar Mass
m= .067(.1)(180.18)= 1.21
Just the steps to Dr.Bob's work :)
12545
Ah, chemistry! The world where atoms and molecules join together to form compounds, like a high school reunion but with more bonding. Let's break it down.
So the initial solution was prepared by dissolving 12.0g of glucose in water until the volume reached 100 ml. The good ol' flask was shaken until everything was nicely mixed.
Now, you've taken a smaller sample of 50.0 ml from this original solution and diluted it all the way up to 0.500 L. Clever move!
To find out how many grams of glucose are in 100 ml of the final solution, we'll use the power of proportions and cross-multiplication. Brace yourself, it's math time!
We can set up a proportion like this:
(12.0g / 100ml) = (x g / 100ml)
Cross-multiplying leads us to:
(12.0g) * (100ml) = (x g) * (100ml)
Now, divide both sides by 100 ml to solve for x:
x g = (12.0g * 100ml) / 100ml
And voila! It turns out that x is equal to... drumroll, please... 12.0 grams! Yep, the amount of glucose in the final 100 ml solution is the same as the amount in the original solution, because you haven't added or taken away any glucose during the diluting process.
So, in conclusion, you've got yourself a nice 12 grams of glucose in that 100 ml of final solution. Enjoy, and may your chemistry experiments be as sweet as a cupcake made of glucose!
To determine the mass of glucose in 100 ml of the final solution, we can use a series of conversions and calculations. Here's the step-by-step process:
Step 1: Calculate the concentration of glucose in the original solution.
The original solution was prepared by dissolving 12.0g of glucose in sufficient water to make a 100 ml solution. Therefore, the concentration of glucose in the original solution is:
Concentration of glucose = mass of glucose / volume of solution
= 12.0g / 100 ml
Note: To make calculations easier, it is better to have the volume of solution in liters. We can convert 100 ml to liters by dividing by 1000:
Volume of solution = 100 ml / 1000
= 0.100 L
Concentration of glucose = 12.0g / 0.100 L
Step 2: Calculate the concentration of glucose in the 50 ml sample.
To do this, we can use the concept of "dilution":
Concentration1 × Volume1 = Concentration2 × Volume2
The concentration of glucose in the original solution (Concentration1) is known, as is the initial volume of the sample (Volume1, which is 50 ml). The final volume of the diluted solution (Volume2) is 0.500 L. We can rearrange the equation to solve for Concentration2 (the concentration of glucose in the diluted solution):
Concentration2 = (Concentration1 × Volume1) / Volume2
= (12.0g / 0.100 L) × (50 ml / 0.500 L)
Note: Again, to facilitate calculations, the volume of the sample (50 ml) should be converted to liters:
Volume1 = 50 ml / 1000
= 0.050 L
Concentration2 = (12.0g / 0.100 L) × (0.050 L / 0.500 L)
Step 3: Calculate the mass of glucose in 100 ml of the final solution.
The concentration of glucose in the diluted solution (Concentration2) is now known. To find the mass of glucose in 100 ml of this solution, we can use the equation:
Mass of glucose = Concentration2 × Volume of solution
= Concentration2 × 100 ml
Note: Once again, it's helpful to convert the volume of the solution (100 ml) to liters:
Volume of solution = 100 ml / 1000
= 0.100 L
Mass of glucose = (12.0g / 0.100 L) × 0.100 L
Simplifying the equation:
Mass of glucose = 12.0g
Therefore, there are 12.0 grams of glucose in 100 ml of the final solution.
12.0 g/100 mL 0riginal.
Take a 50.0 mL aliquot so now you have 6.0 g in the 50.0 mL. That is diluted to 500 mL so now you have 6.0 g in 500 mL. If you take 100 mL of that solution you will have 1/5 of 6.0 = ??