If the decomposition of 3.785 g iron (III) chloride yields 1.302 g iron and 2.483 g chlorine, how many grams of iron and chlorine are produced when 2.175 g iron (III) chloride decomposes?

To find out how many grams of iron and chlorine are produced when 2.175 g of iron (III) chloride decomposes, we can use the concept of proportionality.

First, let's determine the proportion of iron and chlorine produced by decomposing 3.785 g of iron (III) chloride:

Amount of iron produced = 1.302 g
Amount of chlorine produced = 2.483 g

Now, let's set up a proportion to find out the amount of iron and chlorine produced when 2.175 g of iron (III) chloride decomposes:

(1.302 g iron) / (3.785 g iron (III) chloride) = (x g iron) / (2.175 g iron (III) chloride)

Cross-multiplying, we get:

(1.302 g iron) * (2.175 g iron (III) chloride) = (x g iron) * (3.785 g iron (III) chloride)

Simplifying, we have:

x g iron = (1.302 g iron) * (2.175 g iron (III) chloride) / (3.785 g iron (III) chloride)

Evaluating this expression gives:

x g iron = 0.75 g iron

Therefore, when 2.175 g of iron (III) chloride decomposes, approximately 0.75 g of iron is produced.

Similarly, we can find the amount of chlorine produced using the same approach:

(x g chlorine) / (2.175 g iron (III) chloride) = (2.483 g chlorine) / (3.785 g iron (III) chloride)

Cross-multiplying and simplifying, we have:

x g chlorine = (2.483 g chlorine) * (2.175 g iron (III) chloride) / (3.785 g iron (III) chloride)

Evaluating this expression gives:

x g chlorine = 1.43 g chlorine

Therefore, when 2.175 g of iron (III) chloride decomposes, approximately 1.43 g of chlorine is produced.

In summary, when 2.175 g of iron (III) chloride decomposes, approximately 0.75 g of iron and 1.43 g of chlorine are produced.

2FeCl3 3.785g &nbsp 2.175g

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v
2Fe 1.302 &nbsp x
+
3Cl2 2.483 &nbsp y

I would do it this way.
For Fe, x = 1.302 x (2.175/3.785) = 0.758 g
For Cl2 2.175-0.758 = 1.427 g