Assume that the partion compound is 3. Given 400mL of aqueous solution containg 12 g of compound. How many grams of A could be removed from the solution by a single extraction with 200mL of diethyl ether? Also how many total grams can be removed from the aqueous solution with 3 extractions of 67 mL each....
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To find out how many grams of compound A can be removed from the solution by a single extraction with 200mL of diethyl ether, we need to determine the partition coefficient (K).
The partition coefficient (K) is defined as the ratio of the concentration of compound A in the organic phase (diethyl ether) to the concentration of compound A in the aqueous phase (solution). It can be calculated using the formula:
K = (grams of A in organic phase) / (grams of A in aqueous phase)
In this case, we are given that the partition coefficient (K) is 3. This means that for every gram of compound A in the organic phase, there are 3 grams of compound A in the aqueous phase.
Let's calculate the grams of A that can be removed with a single extraction:
1. Calculate the grams of A in the aqueous phase:
grams of A in aqueous phase = 12 g - grams of A in organic phase
2. Calculate the grams of A in the organic phase:
grams of A in organic phase = (K * volume of diethyl ether) / (volume of solution + volume of diethyl ether) * grams of A in aqueous phase
grams of A in organic phase = (3 * 200 mL) / (400 mL + 200 mL) * grams of A in aqueous phase
3. Substitute the value of grams of A in aqueous phase:
grams of A in organic phase = (3 * 200 mL) / (400 mL + 200 mL) * (12 g - grams of A in organic phase)
Simplify the equation:
grams of A in organic phase = (3 * 200 mL) / (600 mL) * (12 g - grams of A in organic phase)
Rearrange the equation:
grams of A in organic phase + (3 * 200 mL) / (600 mL) * grams of A in organic phase = (3 * 200 mL) / (600 mL) * 12 g
Combine like terms:
(1 + (3 * 200 mL) / (600 mL)) * grams of A in organic phase = (3 * 200 mL) / (600 mL) * 12 g
Simplify the equation:
(1 + (3 * 1/3)) * grams of A in organic phase = (1/3) * 12 g
Solve for grams of A in organic phase:
(1 + 1) * grams of A in organic phase = 4 g
Combine like terms:
2 * grams of A in organic phase = 4 g
Divide both sides by 2:
grams of A in organic phase = 2 g
So, a single extraction with 200mL of diethyl ether can remove 2 grams of compound A from the solution.
To determine how many grams of A can be removed from the aqueous solution with 3 extractions of 67 mL each, we can use the same formula and adjust the volume of diethyl ether.
1. Calculate the grams of A in the aqueous phase:
grams of A in aqueous phase = 12 g - grams of A in organic phase
2. Calculate the grams of A in the organic phase for each extraction:
grams of A in organic phase (per extraction) = (K * volume of diethyl ether) / (volume of solution + volume of diethyl ether) * grams of A in aqueous phase
grams of A in organic phase (per extraction) = (3 * 67 mL) / (400 mL + 67 mL) * grams of A in aqueous phase
3. Substitute the value of grams of A in aqueous phase:
grams of A in organic phase (per extraction) = (3 * 67 mL) / (467 mL) * (12 g - grams of A in organic phase)
4. Repeat steps 1-3 for three extractions and sum up the grams of A in each extraction.
grams of A in organic phase (total) = grams of A in organic phase (per extraction - 1) + grams of A in organic phase (per extraction - 2) + grams of A in organic phase (per extraction - 3)
So, by following these steps, you can calculate the total number of grams that can be removed from the aqueous solution using 3 extractions of 67 mL each.
To calculate how many grams of compound A could be removed from the solution by a single extraction with 200 mL of diethyl ether, we need to determine the solubility of compound A in diethyl ether.
Assuming that compound A is soluble in diethyl ether, we can calculate the amount of compound A that can be removed using the following formula:
Amount of compound A removed = (volume of diethyl ether / total volume) x total mass of compound A
Given:
Volume of diethyl ether (Vether) = 200 mL
Total volume (Vtotal) = 400 mL
Total mass of compound A (Mtotal) = 12 g
Substituting the given values into the formula:
Amount of compound A removed = (200 mL / 400 mL) x 12 g
Amount of compound A removed = 0.5 x 12 g
Amount of compound A removed = 6 g
Therefore, a single extraction with 200 mL of diethyl ether could remove 6 grams of compound A from the solution.
Now, let's calculate how many grams of compound A can be removed from the aqueous solution with 3 extractions of 67 mL each.
Using the same formula as before:
Amount of compound A removed in one extraction = (volume of diethyl ether / total volume) x total mass of compound A
Amount of compound A removed in one extraction = (67 mL / 400 mL) x 12 g
Amount of compound A removed in one extraction = 0.1675 x 12 g
Amount of compound A removed in one extraction = 2.01 g
Since we are performing 3 extractions, we can calculate the total amount of compound A removed:
Total amount of compound A removed = Amount of compound A removed in one extraction x number of extractions
Total amount of compound A removed = 2.01 g x 3
Total amount of compound A removed = 6.03 g
Therefore, with 3 extractions of 67 mL each, a total of 6.03 grams of compound A can be removed from the aqueous solution.