if a plane leaves a horizontal at an angle of 60 degrees and at 1 minute reaches a point of 12 miles how fast is the plane going....
"reaches a point of 12 miles" is ambiguous.
Do you mean 12 miles in the air (elevation), perpendicular to the ground?
Or, do you mean 12 miles from the point at which the plane took off?
a rocket ascends at angle of 60 degrees
with the horizontal. after 1 minute
it is directly over a point that is a horizontal distance of 12 miles from
launch point. what is the speed of the
rocket? thanks
Cos 60 = X/12 where x is the length of the hypotenuse of the triangle. That is the distance traveled in 1 min. Post your work if you get stuck.
To find the speed of the rocket, we need to use trigonometry and the given information.
In this scenario, the distance traveled by the rocket in 1 minute is the horizontal distance of 12 miles. We can use the cosine function to find the length of the hypotenuse (distance traveled by the rocket) with respect to the angle of 60 degrees.
The formula for cosine is:
cos(angle) = adjacent side / hypotenuse
We know that the adjacent side is the horizontal distance of 12 miles. Let's substitute these values into the formula:
cos(60 degrees) = 12 miles / hypotenuse
Now, we can solve for the hypotenuse (distance traveled by the rocket) by isolating it:
hypotenuse = 12 miles / cos(60 degrees)
To calculate this, you can use a scientific calculator or an online trigonometry calculator. Plugging in the values:
hypotenuse = 12 miles / 0.5
=> hypotenuse = 24 miles
Therefore, the speed of the rocket is 24 miles per minute.