so t=0 or t=-1 or t=1, and the solution set is {0,-1,1}?
yes.
thanks
Yes, your approach is correct. To solve the equation t^3 - t = 0, you factored it as t(t^2-1)=0. Then you further factored t^2-1 as (t-1)(t+1) using the difference of squares formula. Finally, you set each factor equal to zero to find the values of t that make the equation true. So, the solutions to the equation are t=0 and t=1, which can be written as {0,1}.