Reflective sets of angles

Given: <ABC is congruent to <EFG
<1 is congruent to <3
Prove: <2 is congruent to <4

Statements: Reasons:
1.) <ABC is congruent to <EFG 1.) Given
(m<ABC is congruent to m<EFG)
<1 is congruent to <3
(m<1 is congruent to m<3)

Please help me finish the proofs!
Thanks!

To prove that <2 is congruent to <4, we can use the Transitive Property of Congruence. The Transitive Property states that if two angles are congruent to the same angle, then they must be congruent to each other.

Here's how to complete the proof:

2.) <ABC is congruent to <EFG 2.) (Given)
(m<ABC is congruent to m<EFG)

3.) m<ABC is congruent to m<EFG 3.) (Angle Congruence Property)

4.) <1 is congruent to <3 4.) (Given)
(m<1 is congruent to m<3)

5.) <ABC is congruent to <EFG, <1 is congruent to <3 5.) (Combining Statements 1 and 4)

Now, we can use the Transitive Property to conclude that <2 is congruent to <4:

6.) <ABC is congruent to <EFG, <1 is congruent to <3, m<ABC is congruent to m<EFG, m<1 is congruent to m<3, and <1 is congruent to <3 6.) (Combining Statements 2, 3, and 5)

7.) <2 is congruent to <4 7.) (Transitive Property of Congruence, using Statement 6)

Therefore, we have proved that <2 is congruent to <4.

To continue the proof, you can utilize the transitive property of angle congruence. Here are the remaining steps:

2.) <ABC is congruent to <EFG 1.) Given
(m<ABC is congruent to m<EFG)
<1 is congruent to <3
(m<1 is congruent to m<3)

3.) <1 is congruent to <3 3.) Given
(m<1 is congruent to m<3)

4.) <3 is congruent to <2 4.) Given
(m<3 is congruent to m<2)

5.) <1 is congruent to <2 5.) Transitive Property (steps 3 and 4)

Therefore, the proof is complete, and it is proven that <2 is congruent to <4.