A ball falls from rest on another planet. It falls 30 m, reaching a velocity of 15m/s. Determine its acceleration.
vf^2=2*"g"*distance
solve for g.
To determine the acceleration of the ball, we can use the kinematic equation that relates displacement (d), initial velocity (v₀), final velocity (v), and acceleration (a):
d = (v² - v₀²) / (2a)
Here, the initial velocity (v₀) is 0 m/s since the ball falls from rest. The final velocity (v) is 15 m/s, and the displacement (d) is 30 m. Plugging these values into the equation, we can solve for the acceleration:
30 = (15² - 0²) / (2a)
First, let's simplify the equation:
30 = 225 / (2a)
Next, we can cross-multiply:
30 * 2a = 225
60a = 225
Now, solve for "a" by dividing both sides of the equation by 60:
a = 225 / 60
a ≈ 3.75 m/s²
Therefore, the acceleration of the ball is approximately 3.75 m/s².