Please reply to this one urgently: Horizontally moving plane at 600kmph speed, at a height of 1960km, drops a package at point A and it drop at point B. Find the distance between A and B.
To find the distance between points A and B, we need to determine the horizontal distance traveled by the plane. Since the plane is moving horizontally, its speed and the time it takes to travel a certain distance are the only factors we need to consider.
To find the time it takes for the package to drop from the plane at point A to the ground at point B, we need to calculate the time it takes for the package to fall vertically. We can use the equations of motion to find this time.
First, let's convert the speed of the plane from km/h to m/s:
600 km/h = (600 * 1000) m/3600 s = 167 m/s
Now, let's determine the time taken by the package to fall from point A to the ground at point B. We can use the equation h = (1/2) * g * t^2, where h is the height, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time. Rearranging the equation, we have t = sqrt(2h / g).
Distance traveled by the plane (horizontal distance) = speed of the plane * time taken for the package to fall.
Now, substituting the values into the equation, we have:
t = sqrt(2 * 1960 km / 9.8 m/s^2)
= sqrt(2 * 1960000 m / 9.8 m/s^2)
= sqrt(4000000 m / 9.8 m/s^2)
= sqrt(408163.2653 s^2)
≈ 639.15 s
Distance traveled by the plane = speed of the plane * time taken for the package to fall
= 167 m/s * 639.15 s
≈ 106,476.05 m
Therefore, the distance between point A and point B is approximately 106,476.05 meters.