determine the specific heat of a material if a 35.0 g sample absorbed 48.0 J as it was heated from 20 Celsius to 40 Celsius.

To determine the specific heat of a material, you can use the formula:

q = m * c * ΔT

Where:
q = heat energy absorbed (in J)
m = mass of the sample (in g)
c = specific heat of the material (in J/g°C)
ΔT = change in temperature (in °C)

In this case, you are given:
q = 48.0 J
m = 35.0 g
ΔT = 40°C - 20°C = 20°C

Now we can rearrange the formula to solve for c:

c = q / (m * ΔT)

Substituting the given values:

c = 48.0 J / (35.0 g * 20°C)
c = 48.0 J / (700 g°C)
c ≈ 0.069 J/g°C

Therefore, the specific heat of the material is approximately 0.069 J/g°C.

To determine the specific heat of a material, you can use the formula:

q = m * c * ΔT

where:
q is the heat absorbed or released by the material,
m is the mass of the material,
c is the specific heat capacity of the material, and
ΔT is the change in temperature.

In this case, you are given the mass of the sample (m = 35.0 g), the heat absorbed (q = 48.0 J), and the change in temperature (ΔT = 40°C - 20°C = 20°C).

Now, we can rearrange the formula to solve for the specific heat capacity (c):

c = q / (m * ΔT)

Substituting the given values:

c = 48.0 J / (35.0 g * 20°C)

Now, let's calculate the specific heat:

c = 48.0 J / (35.0 g * 20°C)
c ≈ 0.0686 J/(g°C)

Therefore, the specific heat of the material is approximately 0.0686 J/(g°C).

q = mass x sp.h. x (Tfinal-Tinitial).