What is the net ionic equation for Phosphate ion + ammonium molybdate in the presence of nitric acid?
H3PO4 + (NH4)2MoO4 + H+ → (NH4)3PO4•12MoO3•2H2O + NH4+ + H2O
To determine the net ionic equation for the reaction between phosphate ion (PO4^3-) and ammonium molybdate in the presence of nitric acid (HNO3), we need to consider the dissociation of the compounds involved.
The dissolution of ammonium molybdate ((NH4)2MoO4) can be represented as:
(NH4)2MoO4(s) → 2 NH4+(aq) + MoO4^2-(aq)
Phosphate ion (PO4^3-) and nitric acid (HNO3) both readily dissociate in water:
PO4^3-(aq) ↔ HPO4^2-(aq) + OH^-(aq)
HNO3(aq) ↔ H+(aq) + NO3^-(aq)
Now, let's combine the above equations to write the net ionic equation:
The phosphate ion reacts with the molybdate ion (MoO4^2-) to form an insoluble compound called ammonium phosphomolybdate, which can be represented as (NH4)3PO4·12MoO3(s). The formation of this compound is represented as:
3 NH4+(aq) + PO4^3-(aq) + 12 MoO4^2-(aq) → (NH4)3PO4·12MoO3(s)
The net ionic equation is obtained by removing the spectator ions (ions that appear unchanged on both sides of the equation), which in this case are NH4+ and MoO4^2-. Therefore, the net ionic equation is:
PO4^3-(aq) → (NH4)3PO4·12MoO3(s)
To write the net ionic equation for the reaction between phosphate ion (PO4^3-) and ammonium molybdate in the presence of nitric acid, you need to first write the balanced chemical equation for the overall reaction.
The chemical formula for phosphate ion is PO4^3-, and the chemical formula for ammonium molybdate is (NH4)2MoO4. The presence of nitric acid (HNO3) suggests that it will be a part of the reaction as well.
So, the balanced chemical equation for the reaction can be written as:
3 NH4+ + PO4^3- + 12 HNO3 + MoO4^2- → (NH4)3PO4·12MoO3 + 12 NO3- + 12 H2O
Now, to write the net ionic equation, you need to eliminate the spectator ions, which are the ions that appear on both sides of the equation in the same form. In this case, the spectator ions are NH4+ and NO3-.
After removing the spectator ions, the net ionic equation for the reaction is:
PO4^3- + 12 H+ + MoO4^2- → (NH4)3PO4·12MoO3 + 12 H2O
This equation represents the essential chemical changes that occur during the reaction, without including the spectator ions.