A car traveling in a straight line has a velocity of +4.9 m/s. After an acceleration of 0.50 m/s2, the car's velocity is +7.3 m/s. In what time interval did the acceleration occur?
acceleration=(Vf-Vi)/time
time=(Vf-Vi)/acceleration
^ That is just an equation, it does not even answer the question..
I don't mean to be rude but even if you know the equation you can't answer the question if you do not know how to apply it.
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To find the time interval during which the acceleration occurred, we can use the following kinematic equation:
v = u + at
where:
v = final velocity
u = initial velocity
a = acceleration
t = time interval
Given:
u = +4.9 m/s
v = +7.3 m/s
a = 0.50 m/s²
Substituting the given values into the equation, we have:
7.3 = 4.9 + 0.50t
Solving this equation for t will give us the time interval during which the acceleration occurred.
First, we subtract 4.9 from both sides of the equation:
7.3 - 4.9 = 0.50t
2.4 = 0.50t
Next, we divide both sides of the equation by 0.50:
2.4/0.50 = t
This gives us:
t = 4.8 seconds
Therefore, the time interval during which the acceleration occurred is 4.8 seconds.