Pb+NO3+Na2SO4-->?
Pb + NO3^- + Na2SO4 ==> PbSO4(s) + NO3^-
To determine the product of the given chemical equation, we need to balance the equation first. Let's start by identifying the elements present on each side of the equation:
On the left side of the equation (reactant side):
- Pb (lead)
- NO3 (nitrate)
- Na2SO4 (sodium sulfate)
On the right side of the equation (product side), we need to determine the products formed.
Next, we can balance the equation by ensuring the same number of each type of atom is present on both sides.
Balancing the equation:
Pb + 2NO3 + Na2SO4 -> Pb(NO3)2 + Na2SO4
The balanced equation shows that lead (Pb) reacts with sodium sulfate (Na2SO4) to produce lead(II) nitrate (Pb(NO3)2) and sodium sulfate (Na2SO4) as the products.
Therefore, the balanced chemical equation is:
Pb + 2NO3 + Na2SO4 -> Pb(NO3)2 + Na2SO4