How would you prepare a 250 mL solution of . 45 M from a stock solution of 5.5 M?
Is that 45M or 0.45M?
mL x M = mL x M
.45M
The formula I showed is for 0.45M.
.45M X 250 Ml/ 5.5M= 21 ML of 5.5M stock solution.
To prepare a 250 mL solution of 0.45 M concentration from a stock solution of 5.5 M, you can use the formula:
C1V1 = C2V2
where C1 is the concentration of the stock solution, V1 is the volume of the stock solution to be used, C2 is the desired concentration, and V2 is the desired volume of the final solution.
In this case, we know:
C1 = 5.5 M (stock solution concentration)
V1 = unknown (volume of the stock solution to be used)
C2 = 0.45 M (desired concentration of the final solution)
V2 = 250 mL (desired volume of the final solution)
Rearranging the formula, we have:
V1 = (C2 * V2) / C1
Plugging in the values, we get:
V1 = (0.45 M * 250 mL) / 5.5 M
V1 = (0.45 * 250) / 5.5
V1 ≈ 20.45 mL
Therefore, to prepare a 250 mL solution of 0.45 M concentration from a stock solution of 5.5 M, you need to measure approximately 20.45 mL of the stock solution and then add enough solvent (usually water) to reach a final volume of 250 mL.