solve for x:
2x+3y=8
subtract 3y from 3y and what else do you subtract it from? divide what numbers by 2?
2x+3y=8
Bob said to subtract 3y from each side:
2x=-3y+8
Then divide by 2..
x=(-3y+8)/2
To solve for x in the equation 2x + 3y = 8, we need to isolate x on one side of the equation.
Step 1: Start with the given equation: 2x + 3y = 8.
Step 2: To isolate x, we need to get rid of the term with y. We can do this by subtracting 3y from both sides of the equation:
2x + 3y - 3y = 8 - 3y.
Simplifying this equation gives us: 2x = 8 - 3y.
Step 3: Now, we need to isolate x by getting rid of the coefficient 2. We can do this by dividing both sides of the equation by 2:
(2x)/2 = (8 - 3y)/2.
Simplifying this equation gives us: x = (8 - 3y)/2.
So, the solution for x is x = (8 - 3y)/2.
subtract 3y from each side, then
divide each side by 2