you push with a 40-N horizontal force on a 2-kg box of coffee resting on a horizontal surface. The force of friction on the box is 12 N. Show that the acceleration is 4 m/s^2
Net force after friction
= 40N - 12N=28N
mass = 2kg
Use F=ma and solve for a (acceleration).
Note: not sure if the question is correct, either the mass=7kg or acceleration = 14 m/s².
To calculate the acceleration of the coffee box, we can use Newton's second law of motion, which states that the net force on an object is equal to the mass of the object multiplied by its acceleration.
Given information:
- Applied force: 40 N
- Frictional force: 12 N
- Mass of the box: 2 kg
To find the net force acting on the box, we need to subtract the force of friction from the applied force:
Net force = Applied force - Frictional force
= 40 N - 12 N
= 28 N
Now, we can use Newton's second law to calculate the acceleration:
Net force = Mass x Acceleration
Rearranging the formula, we can solve for acceleration:
Acceleration = Net force / Mass
Substituting the values we know:
Acceleration = 28 N / 2 kg
= 14 m/s^2
Therefore, the acceleration of the coffee box is 14 m/s^2.