please HELP!!!
What is the magnitude of the momentum of a baseball (m = 1.450 kg) traveling at a speed of 102 mi/h? Express your answer in SI units.
I am unsure where to start
convert mi/hr into meters/sec.
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102 miles/hr in m/s
P = mv
P = 1450(kg) x 102(m/s) = 147900 (kg m/s)
To find the magnitude of the momentum of the baseball, you can follow these steps:
Step 1: Convert the speed from miles per hour (mi/h) to meters per second (m/s). You can use the conversion factor: 1 mi/h = 0.44704 m/s.
So, 102 mi/h * 0.44704 m/s = 45.93248 m/s (rounding to the appropriate number of decimal places).
Step 2: Recall that the momentum (p) of an object is given by the equation p = m * v, where m is the mass and v is the velocity.
Given the mass of the baseball (m = 1.450 kg) and the velocity you just calculated (v = 45.93248 m/s), you can substitute these values into the equation.
p = 1.450 kg * 45.93248 m/s
Step 3: Calculate the product of the mass and velocity.
p = 66.555456 kg∙m/s
The magnitude of the momentum of the baseball traveling at a speed of 102 mi/h is approximately 66.555456 kg∙m/s.