The concentration of sodium chloride in an aqueous solution that is 2.23 M and that has a density of

1.01 g/mL is __ % by mass.

concentration by mass..

mass NaCl=2.23*formulamassNaCl (per liter

mass solution=1liter*1010g/liter

percent= massNaCl/masssolution

2.23 x 58.443 = 130.33

mass is 1010g

130.33/1140.33= 11.4
but 12.9 is the right answer...

Look at Bob P's work. mass solution is 1010g, (you added 1010+130.33=1140.33 which isn't correct).

130.33/1010 = 12.9%

sorry, im used to adding together once you convert to grams...

To find the percentage by mass of sodium chloride in the solution, we first need to determine the mass of sodium chloride present in a given volume of the solution.

Given information:
- Concentration of sodium chloride (NaCl) in the solution: 2.23 M
- Density of the solution: 1.01 g/mL

We can start by converting the concentration from moles per liter (M) to moles per milliliter (mL). This conversion is necessary because the density is given in grams per milliliter (g/mL).

To convert from M to moles/mL, we need to divide the concentration by 1000 since there are 1000 mL in a liter.
Concentration in moles/mL = 2.23 M / 1000 = 0.00223 moles/mL

Next, we need to find the mass of sodium chloride in 1 mL of the solution. To do this, we multiply the concentration in moles/mL by the molar mass of sodium chloride.

The molar mass of NaCl can be found in the periodic table:
- Atomic mass of Na = 22.99 g/mol
- Atomic mass of Cl = 35.45 g/mol

So, the molar mass of NaCl = 22.99 + 35.45 = 58.44 g/mol

Now, we can calculate the mass of NaCl in 1 mL of the solution:
Mass of NaCl in 1 mL = 0.00223 moles/mL * 58.44 g/mol = 0.1296 g/mL

Finally, to find the percentage by mass of NaCl in the solution, we divide the mass of NaCl by the total mass of the solution and multiply by 100.

Total mass of the solution in 1 mL = volume (1 mL) * density (1.01 g/mL) = 1.01 g/mL

Percentage by mass of NaCl in the solution = (0.1296 g/mL / 1.01 g/mL) * 100 = 12.8%

Therefore, the concentration of sodium chloride in the aqueous solution is approximately 12.8% by mass.