Help! i am having trouble finding the order pair for the first pair I have (0,-12), but I am not sure this is correct
9x-4y= -12 and 4y-9x=12
9x - 4y = - 12
-9x + 4y = 12
Add the 2 Eqs and get:
0 + 0 = 0
There are no solutions, because the 2 Eqs are identical and have = slopes and y-intercepts.
Slope-int. form:
y = (9/4)x + 3
y = (9/4)x + 3
To find the order pair for the equation 9x - 4y = -12, you can follow these steps:
Step 1: Rearrange the equation in terms of y to isolate y:
9x - 4y = -12
Subtract 9x from both sides:
-4y = -12 - 9x
Divide both sides by -4:
y = (9x - 12) / 4
Step 2: Substitute the value of x from the given order pair (0, -12) into the equation to find y:
y = (9(0) - 12) / 4
Simplify:
y = -12 / 4
y = -3
Therefore, the order pair for the equation 9x - 4y = -12 is (0, -3).
Next, let's check the other equation, 4y - 9x = 12, to see if it also satisfies the given order pair:
Substitute the values x = 0 and y = -3 into the equation:
4(-3) - 9(0) = 12
Simplify:
-12 = 12
Since -12 does not equal 12, the order pair (0, -3) does not satisfy the equation 4y - 9x = 12. Therefore, the first equation 9x - 4y = -12 is correct, and the order pair (0, -3) is the correct solution for it.