Solve Calculate the grams of carbon of 77.7 g of propane?
Use proportions:
Mass of carbon
=77.7g *(sum of RAM of carbon atoms in propane)/(Mr of propane)
RAM=relative atomic mass
Mr = relative molecular mass
C3H8 = propane.
%C = (3*atomic mass C)/molar mass C3H8.
Then g C = %C (as a fraction) x 77.7.
To calculate the grams of carbon in 77.7 g of propane, you need to know the molecular formula of propane, which is C3H8.
Propane has three carbon atoms, so you can use the molar mass of carbon to determine the grams of carbon in one molecule of propane. The molar mass of carbon is approximately 12.01 g/mol.
First, calculate the molar mass of propane:
Molar mass of carbon (C) = 12.01 g/mol
Molar mass of hydrogen (H) = 1.01 g/mol
Molar mass of propane (C3H8) = (3 × molar mass of carbon) + (8 × molar mass of hydrogen)
= (3 × 12.01 g/mol) + (8 × 1.01 g/mol)
= 36.03 g/mol + 8.08 g/mol
= 44.11 g/mol
Now, you can calculate the grams of carbon in 77.7 g of propane using the following formula:
Grams of carbon = (molar mass of carbon × number of carbon atoms in propane) / molar mass of propane
Grams of carbon = (12.01 g/mol × 3) / 44.11 g/mol
= 36.03 g/mol / 44.11 g/mol
= 0.817 g
Therefore, there are approximately 0.817 grams of carbon in 77.7 grams of propane.
To calculate the grams of carbon in 77.7 g of propane, we need to know the molecular formula of propane, which is C3H8. This means that each molecule of propane contains three carbon atoms.
To find the grams of carbon, we need to calculate the molar mass of carbon (C) and then consider the ratio between carbon and propane.
The molar mass of carbon is approximately 12.01 g/mol. This means that each mole of carbon weighs 12.01 grams.
Since there are three carbon atoms in one molecule of propane (C3H8), we need to multiply the molar mass of carbon by 3.
Calculating the grams of carbon:
Grams of carbon = (number of carbon atoms) * (molar mass of carbon)
Grams of carbon = 3 * 12.01 g/mol
Grams of carbon = 36.03 g
Therefore, in 77.7 g of propane, there are approximately 36.03 g of carbon.