A student bikes to school by traveling first d_N = 1.10 {miles} north, then d_W = 0.500{miles} west, and finally d_S = 0.200 {miles} south.
You will now find the same quantity algebraically, without the need to use much geometry. Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking.
Let d_vec_N be the displacement vector corresponding to the first leg of the student's trip. Express d_vec_N in component form.
Express your answer as two numbers separated by a comma (e.g., 1.0,2.0). By convention, the x component is written first.
I figured this out. For those that may need help with a question like this. Because of the North direction being the displacement vector... there was a 90 degree angle. So...
(1.1)(cos90) = 0
(1.1)(sin90) = 1.1
Answer: (0, 1.1)
That's wrong when you put it in.
To express the displacement vector d_vec_N in component form, we need to determine the x and y components.
Given:
d_N = 1.10 miles (north)
Since we are using the north direction as the positive y direction, the y component is positive and the x component is zero.
Therefore, the displacement vector d_vec_N can be expressed in component form as (0.0, 1.10).
To express the displacement vector d_vec_N in component form, we need to break it down into its x and y components.
The displacement vector d_vec_N is given as 1.10 miles north. Since north is in the positive y direction, the y component of d_vec_N would be +1.10 miles. The x component would be 0, as there is no displacement in the x direction (west or east).
Therefore, the displacement vector d_vec_N can be expressed in component form as (0, 1.10). The x component is 0 miles, and the y component is 1.10 miles.