Calculate the molality of CsCl in a 6% by mass aqueous solution. Answer in units of m.

6% CsCl means 6 g CsCl/100 g soln.

Convert 6g CsCl to moles. That will be in 199-6 = 94 g solvent.
m = moles/kg solvent.
Post your work if you get stuck.

To calculate the molality of CsCl in a 6% by mass aqueous solution, you need to know the molar mass of CsCl and the mass of the solution.

Step 1: Calculate the molar mass of CsCl:
The molar mass of CsCl can be calculated by adding the atomic masses of cesium (Cs) and chlorine (Cl).
- The atomic mass of Cs is 132.91 g/mol.
- The atomic mass of Cl is 35.45 g/mol.
So, the molar mass of CsCl is:
Molar mass of CsCl = (132.91 g/mol) + (35.45 g/mol) = 168.36 g/mol

Step 2: Calculate the mass of CsCl in the solution:
In a 6% by mass aqueous solution, the mass of CsCl can be calculated by multiplying the mass of the solution by the mass percentage of CsCl.
- Let's assume we have 100 g of the solution (since percentage is given by mass)
- 6% of the solution is CsCl:
Mass of CsCl = (6 g CsCl / 100 g solution) * 100 g solution = 6 g CsCl

Step 3: Calculate the molality of CsCl:
Molality is the ratio of moles of solute to the mass of the solvent (in kilograms). Since CsCl is the solute, and water is the solvent, we need to convert the mass of the solvent to kilograms. The molar mass of water is 18.015 g/mol.

- Moles of CsCl = (Mass of CsCl) / (Molar mass of CsCl)
= 6 g / 168.36 g/mol
= 0.0356 mol

- Mass of Water = Mass of Solution - Mass of CsCl
= 100 g - 6 g
= 94 g

- Mass of Water in kg = Mass of Water / 1000
= 94 g / 1000
= 0.094 kg

- Molality of CsCl = Moles of CsCl / Mass of Water in kg
= 0.0356 mol / 0.094 kg
= 0.379 m

Therefore, the molality of CsCl in the 6% by mass aqueous solution is 0.379 m.