What is the total molar concentration of ions in a .200M solution of AlCl3
Al = 0.200 M
Cl = 3 x 0.200 = 0.600
total = ??
is it .800?
yes
To find the total molar concentration of ions in a solution of AlCl3, we need to consider how AlCl3 dissociates in water.
AlCl3 is an ionic compound that dissociates into one Al3+ ion and three Cl- ions when it dissolves in water:
AlCl3(s) -> Al3+(aq) + 3 Cl-(aq)
This means that for every one AlCl3 molecule that dissolves, we get one Al3+ ion and three Cl- ions in the solution.
Since the molar concentration of AlCl3 is given as 0.200 M, it means that there are 0.200 moles of AlCl3 per liter of solution.
Since AlCl3 dissociates into one Al3+ ion and three Cl- ions, the molar concentration of both ions will be three times the molar concentration of AlCl3:
Molar concentration of Al3+ ion = 0.200 M * 3 = 0.600 M
Molar concentration of Cl- ion = 0.200 M * 3 = 0.600 M
Therefore, the total molar concentration of ions in the .200 M solution of AlCl3 is 0.600 M for both the Al3+ ion and the Cl- ion.