A sample of gas occupies 3.00 L at 760 torr. Calculate the volume it will occupy at 1.45 atm and the same temperature?
2.07 L
To calculate the new volume of the gas, you can use the combined gas law, which states:
(P1 * V1) / T1 = (P2 * V2) / T2
Where:
P1 = initial pressure (760 torr)
V1 = initial volume (3.00 L)
T1 = initial temperature (constant in this case)
P2 = final pressure (1.45 atm)
V2 = final volume (unknown)
T2 = final temperature (constant in this case)
Since the temperature remains constant, we can simplify the equation to:
(P1 * V1) / T = (P2 * V2) / T
Now we can plug in the known values:
(760 torr * 3.00 L) / T = (1.45 atm * V2) / T
The temperature cancels out, and we are left with:
760 torr * 3.00 L = 1.45 atm * V2
To find V2, we need to rearrange the equation:
V2 = (760 torr * 3.00 L) / 1.45 atm
Now we can calculate the new volume:
V2 = (760 torr * 3.00 L) / 1.45 atm
V2 ≈ 1569 L
Therefore, the gas will occupy approximately 1569 liters at 1.45 atm and the same temperature.