A sample of gas occupies 3.00 L at 760 torr. Calculate the volume it will occupy at 1.45 atm and the same temperature?

2.07 L

To calculate the new volume of the gas, you can use the combined gas law, which states:

(P1 * V1) / T1 = (P2 * V2) / T2

Where:
P1 = initial pressure (760 torr)
V1 = initial volume (3.00 L)
T1 = initial temperature (constant in this case)
P2 = final pressure (1.45 atm)
V2 = final volume (unknown)
T2 = final temperature (constant in this case)

Since the temperature remains constant, we can simplify the equation to:

(P1 * V1) / T = (P2 * V2) / T

Now we can plug in the known values:

(760 torr * 3.00 L) / T = (1.45 atm * V2) / T

The temperature cancels out, and we are left with:

760 torr * 3.00 L = 1.45 atm * V2

To find V2, we need to rearrange the equation:

V2 = (760 torr * 3.00 L) / 1.45 atm

Now we can calculate the new volume:

V2 = (760 torr * 3.00 L) / 1.45 atm

V2 ≈ 1569 L

Therefore, the gas will occupy approximately 1569 liters at 1.45 atm and the same temperature.

P1V1 = P2V2

1234