I had this question last night for Dr. Bob-A fox sees a piece of carrion thrown from a nest 14 m high and goes to get it. Carrion is thrown 1.5 horizontal velocity. Fox is 7. m from base of tree. What is mgnitude of fox's average velocity if it grabscarrion just as it touches ground
Answers: 1.7
3.5
4.2
2.6
Dr. Bob gave me three steps-Find time it takes to fall 14 m-which is 1/2 (9.81) times t^2=1.69
During time, how far horizontally does it goe, given horizontal velocity which is 2.52
How fast does fox have to go to cover the 7 m in falling time which is 7/1.69=4.16 which is 4.2m/s as answer
Correct or no?
Ihad 2.6 last night but that is wrong, I know it-
Please help me-my mom is getting a Physics tutor starting next Monday-Please just walk me through this problem
Thank you
Hi, I posted this under my twin's account by accident-I'm Joelle
Thank you
Sure, I'll be happy to walk you through the problem step by step.
Step 1: Find the time it takes for the object to fall 14 m.
To find the time it takes for an object to fall, we use the formula: d = (1/2)gt^2, where d is the distance fallen, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time taken. Plugging in the values, we have 14 = (1/2)(9.81)t^2. Solving for t, we get t^2 = (2*14)/9.81, which gives t ≈ √(2*14/9.81) ≈ 1.69 seconds.
Step 2: Determine the horizontal distance the object travels during this time.
Given the horizontal velocity of 1.5 m/s, we can use the formula d = vt, where d is the distance traveled horizontally, v is the horizontal velocity, and t is the time. In this case, the time is approximately 1.69 seconds from Step 1. Plugging in the values, we have d = 1.5 * 1.69 ≈ 2.54 meters.
Step 3: Calculate the fox's average velocity.
The average velocity is given by the formula v_avg = d_total / t_total, where d_total is the total distance traveled and t_total is the total time taken. In this case, the total distance is 7 meters (the distance from the base of the tree) and the total time is approximately 1.69 seconds (the time taken for the object to fall). Plugging in the values, we have v_avg = 7 / 1.69 ≈ 4.14 m/s.
Therefore, the correct answer would be approximately 4.14 m/s, which is closest to the answer option 4.2 m/s. So it seems you made a mistake while performing the calculation in Step 3.