Calculate the ratio of the effusion rate of oxygen gas (O2) to that of nitrogen gas (N2). Express your answer in decimal form and calculate your answer to at least four sig figs.
Rate1 / Rate2 = sqrt(Mass2/Mass 1)
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To calculate the ratio of the effusion rate of oxygen gas (O2) to that of nitrogen gas (N2), we can use Graham's law of effusion. According to Graham's law, the ratio of the effusion rates of two gases is equal to the square root of the ratio of their molar masses.
The molar mass of oxygen gas (O2) is approximately 32 g/mol, and the molar mass of nitrogen gas (N2) is approximately 28 g/mol.
Using Graham's law, the ratio of the effusion rate of oxygen gas (O2) to that of nitrogen gas (N2) can be calculated as follows:
Ratio = √(Molar mass of N2 / Molar mass of O2)
Ratio = √(28 g/mol / 32 g/mol)
Ratio = √(0.875)
Ratio ≈ 0.935
Therefore, the ratio of the effusion rate of oxygen gas (O2) to that of nitrogen gas (N2) is approximately 0.935.