In this problem the letters x and y are each one digit numbers. Compare x+y O 19?
Do I put any number for x and y ? please help.
Your answer was no but how do I do this problem?
What does O mean?
So you can use any 1 digit number. For example: I used 2+3. Since 2+3=5 what I did was then re-write my problem to 5 < 9. In the circles, I used a less than sign since 5 is less than 9. But you can use any 1 digit number to add.
That is not an O. That is just a circle for you to fill in your missing sign like greater than or less than, ect...
To solve this problem, you need to compare the sum of two one-digit numbers, x and y, to the number 19.
Here's how you can approach it step by step:
1. Start by assuming any values for x and y. Since the problem states that x and y are one-digit numbers, they can be any number between 0 and 9.
2. Add the values of x and y together.
3. Compare the sum x + y to the number 19.
4. If the sum x + y is greater than 19, then the statement "x + y > 19" is true.
5. If the sum x + y is equal to 19, then the statement "x + y = 19" is true.
6. If the sum x + y is less than 19, then the statement "x + y < 19" is true.
Remember that you need to compare the sum of x and y to 19 in order to answer the question "Compare x + y to 19?"
To solve the problem, you need to find the values of x and y that satisfy the given condition of x+y being greater than 19. However, since the question does not provide any constraints or specific values for x and y, you can choose any one-digit numbers for both x and y.
Here's how you can approach the problem:
1. Choose a value for x: Since x can range from 0 to 9 (as it is a one-digit number), select any number within this range. Let's say you choose x = 5.
2. Choose a value for y: Similar to x, select another one-digit number for y. It should be noted that y can be different or the same number as x. For this example, let's choose y = 8.
3. Calculate x + y: Add the values of x and y together. In this case, x + y = 5 + 8 = 13.
4. Compare x + y with 19: In this example, 13 is less than 19. However, the original question asks if x + y is greater than 19. Since 13 is not greater than 19, the answer to the question "Is x + y > 19?" would be no.
Repeat this process with different values for x and y if you would like to explore various scenarios.